2x^2+62x=720

Solution for 2x^2+62x=720 equation:

2x^2+62x=720

We move all terms to the left:

2x^2+62x-(720)=0

a = 2; b = 62; c = -720;
Δ = b2-4ac
Δ = 622-4·2·(-720)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-98}{2*2}=\frac{-160}{4}
=-40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+98}{2*2}=\frac{36}{4}
=9
$